Although Mitt Romney won Saturday’s Puerto Rico primary with more than 80 percent of the vote, gay candidate Fred Karger out-polled Ron Paul.
Karger received 1.43 percent of the vote, while Paul received 1.22 percent.
In his third primary appearance, this is the first time Karger received more votes than one of the top-tier candidates.
“We spent the past six days campaigning hard in Puerto Rico and it worked,” Karger wrote in a campaign email. “Ron Paul has been in all 20 debates, raised $35 million and has 80 percent name identification, and it looks like we beat him with our message of jobs now, moderation and inclusion.”
Santorum, who said last week that if Puerto Ricans want to be Americans, they should learn English, received 8 percent of the vote. Karger ran TV commercials in Spanish. So some Puerto Rico Republicans are so extreme they would rather vote for a candidate who tells them to change their native, local language than for someone who is gay and moderate on all other issues.
Fewer than 100,000 people are registered as Republicans in Puerto Rico, but 20 delegates were at stake. With more than 50 percent of the votes, Romney gets all of the delegates.
From here, Karger next competes in the April 3 Maryland primary. He also will appear on the ballot in his home-state California primary on June 5.
Later that month he will be one of five candidates on the June 26 Utah ballot. He credits his inclusion there as a result of the work of Utah Log Cabin. Results of that primary will be interesting in the state with the largest Mormon population. After that church funded much of the support for Prop 8 in California that stopped same-sex marriage, Karger started the website Top 10 Craziest Mormon Beliefs.